Hey everyone! Apologies for the long post:
This is new stuff to me as im a couple of months in as a machine operator/programmer (star swiss) and unfortunately I dont have anyone to ask for help. I have a new parting insert from sandvick to use for stainless steel with a .125" bar diameter. I need help determining if I calculated the correct cutting speed.
I was given the following start values for said insert:
MACL 3 070-N 1105
fnx 0.002 in/r (0.002 - 0.003)
hexx 0.002 in/r (0.002 - 0.003)
vcx 730 sfm (800 - 690)
I used the formula from sandvicks website:
n= (Vc × 12)/(3.14 × Dm)
and ended up with 22,318 r/min.
The number seems a little high to me, probable because my main spindle tops at 15,000 RPM.
Am I doing this right or will I need another insert ? Any help is appreciated.
This is new stuff to me as im a couple of months in as a machine operator/programmer (star swiss) and unfortunately I dont have anyone to ask for help. I have a new parting insert from sandvick to use for stainless steel with a .125" bar diameter. I need help determining if I calculated the correct cutting speed.
I was given the following start values for said insert:
MACL 3 070-N 1105
fnx 0.002 in/r (0.002 - 0.003)
hexx 0.002 in/r (0.002 - 0.003)
vcx 730 sfm (800 - 690)
I used the formula from sandvicks website:
n= (Vc × 12)/(3.14 × Dm)
and ended up with 22,318 r/min.
The number seems a little high to me, probable because my main spindle tops at 15,000 RPM.
Am I doing this right or will I need another insert ? Any help is appreciated.