david mabe
Plastic
- Joined
- Jul 18, 2022
Please help me figure this out.
Looking for a formula to estimate required tonnage to impress or coin an impression .045 inches deep into 1018 steel bar stock. I make leather stamping tools and have a 75Ton Ferracute Coing/Impression Press. If yield strength is 32kpsi the design is .45 inches (area) and I want to impress a flower design .045 deep the basic calculation says I need 14,400 psi. Doesn't work though because I know that 50 tons on a hydraulic press didnt cause the metal to flow. I have been impressing the tools under a 180lb drop hammer with steel heated to approximately 1800 degrees.
Point is I saw a formula that took into account the yield strength of the material, material thickness and desired depth of impression. Cant find it now.
Thank you.
Looking for a formula to estimate required tonnage to impress or coin an impression .045 inches deep into 1018 steel bar stock. I make leather stamping tools and have a 75Ton Ferracute Coing/Impression Press. If yield strength is 32kpsi the design is .45 inches (area) and I want to impress a flower design .045 deep the basic calculation says I need 14,400 psi. Doesn't work though because I know that 50 tons on a hydraulic press didnt cause the metal to flow. I have been impressing the tools under a 180lb drop hammer with steel heated to approximately 1800 degrees.
Point is I saw a formula that took into account the yield strength of the material, material thickness and desired depth of impression. Cant find it now.
Thank you.